return statement

Terminates current function and returns specified value to the caller function.

Syntax

Explanation

If the type of the expression is different from the return type of the function, its value is converted as if by assignment to an object whose type is the return type of the function, except that overlap between object representations is permitted:

struct s { double i; } f(void); // function returning struct s
union { struct { int f1; struct s f2; } u1;
        struct { struct s f3; int f4; } u2; } g;
struct s f(void)
{
    return g.u1.f2;
}
int main(void)
{
// g.u2.f3 = g.u1.f2; // undefined behavior (overlap in assignment)
   g.u2.f3 = f();     // well-defined
}

If the return type is a real floating type, the result may be represented in greater range and precision than implied by the new type.

Reaching the end of a function returning void is equivalent to return ; . Reaching the end of any other value-returning function is undefined behavior if the result of the function is used in an expression (it is allowed to discard such return value). For main , see main function .

Keywords

return

Example

#include <stdio.h>
void fa(int i)
{
    if (i == 2)
       return;
    printf("fa():   %d\n", i);
} // implied return;
int fb(int i)
{
    if (i > 4)
       return 4;
    printf("fb():   %d\n", i);
    return 2;
}
int main(void)
{
    fa(2);
    fa(1);
    int i = fb(5);   // the return value 4 used to initializes i
    i = fb(i);       // the return value 2 used as rhs of assignment
    printf("main(): %d\n", i);
}

fa():   1
fb():   4
main(): 2

References

See also