std::chrono::year:: operator+=, std::chrono::year:: operator-=
From cppreference.net
|
constexpr
std::
chrono
::
year
&
operator
+
=
(
const
std::
chrono
::
years
&
y
)
noexcept
;
|
(1) | (since C++20) |
|
constexpr
std::
chrono
::
year
&
operator
-
=
(
const
std::
chrono
::
years
&
y
)
noexcept
;
|
(2) | (since C++20) |
Adds or subtracts y. count ( ) years from the year value.
1)
Equivalent to
*
this
=
*
this
+
y
;
.
2)
Equivalent to
*
this
=
*
this
-
y
;
.
Contents |
Return value
A reference to this
year
after modification.
Notes
If the result would be outside the range
[
-
32767
,
32767
]
, the actual stored value is unspecified.
Example
Run this code
#include <chrono> #include <iostream> int main() { using namespace std::literals::chrono_literals; std::cout << std::boolalpha; std::chrono::year y{2020}; y += std::chrono::years(12); std::cout << (y == 2032y) << ' '; y -= std::chrono::years(33); std::cout << (y == 1999y) << '\n'; }
Output:
true true
See also
|
increments or decrements the year
(public member function) |
|
|
(C++20)
|
performs arithmetic on
year
s
(function) |