std::chrono::operator==,<=>(std::chrono::year_month_day_last)
From cppreference.net
| Defined in header <chrono>
|
||
constexpr bool operator==( const std::chrono::year_month_day_last& x,
const std::chrono::year_month_day_last& y ) noexcept;
|
(1) | (since C++20) |
constexpr std::strong_ordering
operator<=>( const std::chrono::year_month_day_last& x,
const std::chrono::year_month_day_last& y ) noexcept;
|
(2) | (since C++20) |
Compares the two year_month_day_last values x and y. This is a lexicographical comparison: the year() is compared first, then month().
The <, <=, >, >=, and != operators are synthesized from operator<=> and operator== respectively.
Return value
1)
x.year() == y.year() && x.month() == y.month()2)
x.year() <=> y.year() != 0 ? x.year() <=> y.year() : x.month() <=> y.month()Notes
If both x and y represent valid dates (x.ok() && y.ok() == true), the result of the lexicographical comparison is consistent with the calendar order.
Example
Run this code
#include <cassert>
#include <chrono>
#include <iostream>
int main()
{
auto ymdl1{11/std::chrono::last/2020};
auto mdl{std::chrono::last/std::chrono::November};
auto ymdl2{mdl/2020};
assert(ymdl1 == ymdl2);
ymdl1 -= std::chrono::months{2};
ymdl2 -= std::chrono::months{1};
assert(ymdl1 < ymdl2);
}