std::experimental::ranges:: common_reference

Defined in header <experimental/ranges/type_traits>
template < class ... T > struct common_reference ;		(ranges TS)

Determines the common reference type of the types T... , that is, the type to which all the types in T... can be converted or bound. If such a type exists (as determined according to the rules below), the member type names that type. Otherwise, there is no member type . The behavior is undefined if any of the types in T... is an incomplete type other than (possibly cv-qualified) void .

When given reference types, common_reference attempts to find a reference type to which the supplied reference types can all be bound, but may return a non-reference type if it cannot find such a reference type.

• If sizeof... ( T ) is zero, there is no member type .
• If sizeof... ( T ) is one (i.e., T... contains only one type T0 ), the member type names the same type as T0 .
• If sizeof... ( T ) is two (i.e., T... contains two types T1 and T2 ):
  • If T1 and T2 are both reference types, and the simple common reference type S of T1 and T2 (as defined below) exists, then the member type type names S ;
  • Otherwise, if basic_common_reference < T1R, T2R, T1Q, T2Q > :: type exists, where TiR is std:: remove_cv_t < std:: remove_reference_t < Ti >> and TiQ is an alias template such that TiQ < TiR > is Ti , then the member type type names that type;
  • Otherwise, if decltype ( false ? val < T1 > ( ) : val < T2 > ( ) ) , where val is a function template template < class T > T val ( ) ; , denotes a valid type, then the member type type names that type;
  • Otherwise, if ranges:: common_type_t < T1, T2 > is a valid type, then the member type type names that type;
  • Otherwise, there is no member type.
• If sizeof... ( T ) is greater than two (i.e., T... consists of the types T1, T2, R... ), then if ranges :: common_reference_t < T1, T2 > exists, the member type denotes ranges :: common_reference_t < ranges :: common_reference_t < T1, T2 > , R... > if such a type exists. In all other cases, there is no member type .

The simple common reference type of two reference types T1 and T2 is defined as follows:

• If T1 is cv1 X & and T2 is cv2 Y & (i.e., both are lvalue reference types): their simple common reference type is decltype ( false ? std:: declval < cv12 X & > ( ) : std:: declval < cv12 Y & > ( ) ) , where cv12 is the union of cv1 and cv2 , if that type exists and is a reference type.
• If T1 and T2 are both rvalue reference types: if the simple common reference type of T1 & and T2 & (determined according to the previous bullet) exists, then let C denote that type's corresponding rvalue reference type. If std:: is_convertible < T1, C > :: value and std:: is_convertible < T2, C > :: value are both true , then the simple common reference type of T1 and T2 is C .
• Otherwise, one of the two types must be an lvalue reference type A & and the other must be an rvalue reference type B && ( A and B might be cv-qualified). Let D denote the simple common reference type of A & and B const & , if any. If D exists and std:: is_convertible < B && , D > :: value is true , then the simple common reference type is D .
• Otherwise, there's no simple common reference type.

Contents 1 Member types 2 Helper types 3 Specializations 4 Notes 5 Example 6 See also

Member types

Name	Definition
type	the common reference type for all T...

Helper types

template < class ... T > using common_reference_t = typename common_reference < T... > :: type ;
template < class T, class U, template < class > class TQual, template < class > class UQual > struct basic_common_reference { } ;

The class template basic_common_reference is a customization point that allows users to influence the result of common_reference for user-defined types (typically proxy references). The primary template is empty.

Specializations

A program may specialize basic_common_reference<T, U, TQual, UQual> on the first two parameters T and U if std:: is_same < T, std:: decay_t < T >> and std:: is_same < U, std:: decay_t < U >> are both true and at least one of them depends on a program-defined type.

If such a specialization has a member named type , it must be a public and unambiguous member type that names a type to which both TQual < T > and UQual < U > are convertible. Additionally, ranges :: basic_common_reference < T, U, TQual, UQual > :: type and ranges :: basic_common_reference < U, T, UQual, TQual > :: type must denote the same type.

A program may not specialize basic_common_reference on the third or fourth parameters, nor may it specialize common_reference itself. A program that adds specializations in violation of these rules has undefined behavior.

Notes

This section is incomplete

Example

This section is incomplete Reason: no example

See also

common_type (C++11)	determines the common type of a group of types (class template)
common_type	determine the common type of a set of types (class template)
CommonReference	specifies that two types share a common reference type (concept)