std::chrono::year_month_weekday_last:: year, std::chrono::year_month_weekday_last:: month, std::chrono::year_month_weekday_last:: weekday, std::chrono::year_month_weekday_last:: weekday_last
From cppreference.net
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cpp
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chrono
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year month weekday last
C++
Date and time library
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std::chrono::year_month_weekday_last
| Member functions | ||||
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year_month_weekday_last::year
year_month_weekday_last::month
year_month_weekday_last::weekday
year_month_weekday_last::weekday_last
|
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| Nonmember functions | ||||
| Helper classes | ||||
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constexpr
std::
chrono
::
year
year
(
)
const
noexcept
;
|
(1) | (since C++20) |
|
constexpr
std::
chrono
::
month
month
(
)
const
noexcept
;
|
(2) | (since C++20) |
|
constexpr
std::
chrono
::
weekday
weekday
(
)
const
noexcept
;
|
(3) | (since C++20) |
|
constexpr
std::
chrono
::
weekday_last
weekday_last
(
)
const
noexcept
;
|
(4) | (since C++20) |
Retrieves the field values stored in this
year_month_weekday_last
object.
Return value
1)
Returns the stored
std::chrono::year
value.
2)
Returns the stored
std::chrono::month
value.
3)
Returns the stored
std::chrono::weekday
value.
4)
std::
chrono
::
weekday_last
(
weekday
(
)
)
Example
Run this code
#include <chrono> #include <iostream> using namespace std::chrono; int main() { auto ymwdl{Tuesday[last]/November/2022}; auto wdl = ymwdl.weekday_last(); wdl = (wdl.weekday() + days(1))[last]; ymwdl = {ymwdl.year() + years(1), ymwdl.month() - months(2), wdl}; std::cout << year_month_day(ymwdl) << '\n'; }
Output:
2023-09-27