std::chrono::year_month_weekday_last:: operator sys_days, std::chrono::year_month_weekday_last:: operator local_days
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<
cpp
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chrono
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year month weekday last
C++
Date and time library
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std::chrono::year_month_weekday_last
| Member functions | ||||
|
year_month_weekday_last::operator sys_days
year_month_weekday_last::operator local_days
|
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| Nonmember functions | ||||
| Helper classes | ||||
|
constexpr
operator
std::
chrono
::
sys_days
(
)
const
noexcept
;
|
(1) | (since C++20) |
|
constexpr
explicit
operator
std::
chrono
::
local_days
(
)
const
noexcept
;
|
(2) | (since C++20) |
Converts
*
this
to a
std::chrono::time_point
representing the same date as this
year_month_weekday_last
.
1)
If
ok()
is
true
, returns a
sys_days
that represents the last
weekday()
of the
year()
and
month()
. Otherwise, the returned value is unspecified.
2)
Same as
(1)
, but returns
local_days
instead of
sys_days
. Equivalent to
local_days
(
sys_days
(
*
this
)
.
time_since_epoch
(
)
)
.
Example
Run this code
#include <chrono> #include <iostream> using namespace std::chrono; int main() { constexpr auto ymwdl{Tuesday[last]/11/2021}; static_assert(static_cast<local_days>(ymwdl) == static_cast<local_days>(November/30/2021)); // convert from field-based to serial-based to add days constexpr auto sd = static_cast<sys_days>(ymwdl); constexpr year_month_day ymd{sd + days(42)}; std::cout << ymd << '\n'; }
Output:
2022-01-11