std::chrono::year_month_weekday_last::operator+=, std::chrono::year_month_weekday_last::operator-=
From cppreference.net
constexpr std::chrono::year_month_weekday_last&
operator+=( const std::chrono::years& dy ) const noexcept;
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(1) | (since C++20) |
constexpr std::chrono::year_month_weekday_last&
operator+=( const std::chrono::months& dm ) const noexcept;
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(2) | (since C++20) |
constexpr std::chrono::year_month_weekday_last&
operator-=( const std::chrono::years& dy ) const noexcept;
|
(3) | (since C++20) |
constexpr std::chrono::year_month_weekday_last&
operator-=( const std::chrono::months& dm ) const noexcept;
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(4) | (since C++20) |
Modifies the time point *this represents by the duration dy or dm.
1) Equivalent to
*this = *this + dy;.2) Equivalent to
*this = *this + dm;.3) Equivalent to
*this = *this - dy;.4) Equivalent to
*this = *this - dm;.For durations that are convertible to both std::chrono::years and std::chrono::months, the years overloads (1,3) are preferred if the call would otherwise be ambiguous.
Example
Run this code
#include <chrono>
#include <iostream>
using namespace std::chrono;
int main()
{
auto ymwdl{August/Friday[last]/2022};
std::cout << year_month_day{ymwdl} << '\n';
ymwdl += months(2);
std::cout << year_month_day{ymwdl} << '\n';
ymwdl -= years(1);
std::cout << year_month_day{ymwdl} << '\n';
}
Output:
2022-08-26
2022-10-28
2021-10-29
See also
(C++20) |
adds or subtracts a year_month_weekday_last and some number of years or months (function) |